4-2-2 Project Part One: Planning Document First Draft

  1. Introduction: In this section, you will discuss your natural science issue and select resources that you can use to research the issue. This will lead you to the development of a research question related to your issue. Specifically, you should:
    1. Describe the issue in the natural sciences that you have selected to investigate. Why is this issue significant? (You identified this issue in Theme 1, but how would you revise this piece now that you have received instructor feedback and investigated your sources?)
    2. Describe at least three science resources that you could use to investigate the issue you selected. Your sources must be relevant to your issue and must be of an academic nature appropriate for the issue. In your description, consider questions such as: What are the similarities and differences in the content of your sources? What makes them appropriate and relevant for investigating your issue? What was your thought process when you were searching for sources? How did you make choices?
    3. Based on your review of science resources, develop a specific question related to the issue you selected. In other words, what would you like to know more about?
  2. Body: In this section, you will use the natural science resources that you selected to investigate your question, focusing on an appropriate audience and

the scientific principles related to the issue. Make sure to cite your sources. Based on your research:

  1. Identify an audience that would be interested in your issue and the question you developed. For example, who would benefit most from hearing your message, or who could best help in addressing the issue?
  2. Describe how and why you can tailor your message to your audience, providing specific examples. For example, will your audience understand scientific terminology and principles, or will you need to explain them? How will you communicate effectively with your audience?
  3. Identify the natural science principle(s) that apply to your question and issue. For example, if your issue is global climate change, the principle you might identify is that the sun is the primary source of energy for Earth’s climate system.
  4. Explain how the principle(s) you identified apply to your issue and question. In other words, how are the natural science principle(s) you identified relevant to your question and issue?

IV. Provide a reference list that includes all of the science resources you used to investigate your issue and question so far. Ensure that your list is formatted according to current APA guidelines (or another format, with instructor permission).

Topic: Earth-size, habitable-zone planet found hidden in early NASA Kepler data (https://www.sciencedaily.com/releases/2020/04/200416105650.htm)

Research Question: Could this Earth-sized habitable-zoned planet be the start of colonizing planets?

Additional Resources:

Wells-Jensen, S., Miele, J. A., & Bohney, B. (2019). An alternate vision for colonization. Retrieved May 19, 2020, from https://www-sciencedirect-com.ezproxy.snhu.edu/science/article/pii/S0016328718302878?via=ihub

Traphagan, J. W. (2019). Which humanity with space colonization save? Retrieved May 19, 2020, from https://www-sciencedirect-com.ezproxy.snhu.edu/science/article/pii/S0016328718302623?via%3Dihub

Campa, R., Szocik, K., & Braddock, M. (2019). Why space colonization will be fully automated. Retrieved May 19, 2020, from https://www-sciencedirect-com.ezproxy.snhu.edu/science/article/pii/S0040162518317281?via%3Dihub

 
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Discussion

Discussion 1:  ONE COPY

Answer the following questions

1. What are Object-Oriented Concepts
2. What is Use Case Modeling and UML
3. What is an Activity Diagram – what would it look like when documenting the activities in Washing a Car or Fast-Food Purchases?

400 words

apa

plagiarism

grammar

Discussion 2 : ONE COPY

Answer the following questions

4. What is a Sequence Diagram – what would it look like when documenting the sequences in Washing a Car or Fast-Food Purchases?
5. What is a Communication/Collaboration Diagram – what would it look like when documenting the communications between players when Washing a Car or Fast-Food Purchases?
6. What is a StateChart Diagram?

apa

400 words.

plagiarism

grammar

 
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CST 610 Proj 2

Project 2 Scenario

Assessing Information System Vulnerabilities and Risk

You are an information assurance management officer (IAMO) at an organization of your choosing. One morning, as you’re getting ready for work, you see an email from Karen, your manager. She asks you to come to her office as soon as you get in. When you arrive to your work, you head straight to Karen’s office. “Sorry for the impromptu meeting,” she says, “but we have a bit of an emergency. There’s been a security breach at the Office of Personnel Management.”

We don’t know how this happened, but we need to make sure it doesn’t happen again, says Karen. You’ll be receiving an email with more information on the security breach. Use this info to assess the information system vulnerabilities of the Office of Personnel Management.

At your desk, you open Karen’s email. She’s given you an OPM report from the Office of the Inspector General, or OIG. You have studied the OPM OIG report and found that the hackers were able to gain access through compromised credentials. The security breach could have been prevented if the Office of Personnel Management, or OPM, had abided by previous auditing reports and security findings. In addition, access to the databases could have been prevented by implementing various encryption schemas and could have been identified after running regularly scheduled scans of the systems.

Karen and the rest of the leadership team want you to compile your findings into a Security Assessment Report, or SAR. You will also create a Risk Assessment Report, or RAR, in which you identify threats, vulnerabilities, risks, and likelihood of exploitation and suggested remediation.

 
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MaxQDA

For this assignment, assume the role of a researcher in the qualitative analysis phase of the study. The data are gathered imported into MAXQDA for analysis. At this point, there are parent codes and sub-codes. However, the software requires human intervention to move past codes to categories and subsequently themes. Clearly, a category of “interview guide topics” cannot be used in the presentation of research results. In this assignment, you will access MAXQDA and practice creating categories and themes.

General Requirements:

Use the following information to ensure successful completion of the assignment:

  • Refer to the document, “Using MAXQDA Assignment Resource,” located in the Course Materials for this topic.
  • This assignment requires the use of MAXQDA software available in the DC. A link to the software is in the Course Materials for this topic.
  • Refer to “Getting Started Video Tutorial” found in the Course Materials for this topic.
  • Doctoral learners are required to use APA style for their writing assignments. The APA Style Guide is located in the Student Success Center.
  • This assignment uses a rubric. Please review the rubric prior to beginning the assignment to become familiar with the expectations for successful completion.
  • This assignment requires that at least two additional scholarly research sources related to this topic, and at least one in-text citation from each source be included.
  • You are required to submit this assignment to Turnitin. Refer to the directions in the Student Success Center.

Directions:

Complete this assignment according to the directions in the document, “Using MAXQDA Assignment Resource.”

 
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Ensuring Future Success: Reflection

Name: Course: Date: Instructor:

Topic 7 Ensuring Future Success

Part 1: Reflection

During the past few weeks, you have had the opportunity to develop a plan for success as a student here at GCU and beyond graduation. Analyze your academic, spiritual, and career goals from Topic 4 Purpose Plan. Complete the following prompts directly on this document—the box will expand as needed. Based on your analysis, in 75-100 words total, describe what three action steps you will need to take in order to achieve your academic goals.

 

Based on your analysis, in 75-100 words total, describe what three action steps you will need to take in order to achieve your spiritual goals.

Based on your analysis, in 75-100 words total, describe what three action steps you will need to take in order to achieve your career goals.

How well are you working towards achieving your academic, spiritual, and career goals? Explain. What changes might you make? (75-100 words total)

1. Academic Goals –

2. Spiritual Goals –

3. Career Goals –

Describe HOW you will know you are achieving your goals. (75-100 words total) 1. Academic Goals –

2. Spiritual Goals –

3. Career Goals –

 

 

Part 2: Publish Your Career Connections Profile Career Connections is one of the primary systems you will use during your time at Grand Canyon University to help you navigate and carry out your academic, career, and spiritual success plans. One of the key features of the system is to have a published profile, which allows you to interact with and be found by employers seeking students like you! To complete this assignment, navigate to your Career Connections account via the widget you added to your student portal for the Topic 4 assignment.

Watch this video for instructions on how to publish your profile: https://youtu.be/yLblus8jM8U

Then, publish your profile. Take a screenshot of your published profile and provide it below:

 
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IHS Mid Term

MID TERM Assignment

1. Question: Choose one natural disaster and one terrorism disaster, each of which had a significant impact on the practice of emergency management and describe that influence.

 

2. Question: Homeland security as established in the aftermath of September 11th changed not only our government, but also our way of life. In what negative and positive ways has homeland security affected you personally?

 

 

3. Question: Is the function of homeland security maintained wholly by the Department of Homeland Security, or is this function shared among other governmental and non-governmental agencies? Explain your answer.

 

4. Question: What agencies have been transferred intact into the DHS structure? How, if at all, have their missions changed as a result?

 

 

5. Question: List and describe the various intelligence gathering methods.

 

6. Question: Do you think that the nature of the creation of the Department of Homeland Security in the aftermath of the 9/11 attacks affected the all-hazards mission of FEMA? Why or why not?

 

 

7. Question: How do Federal agencies outside of DHS participate in Homeland Security? Give three examples to support your answer.

 

8. Question: Explain briefly how FEMA failed to garner lead agency status for the terrorism hazard.

 

 

9. Question: Explain in your own words what the Intelligence Community is and provide examples of IC members.

 

10. Question: Describe the role of the “3 Commissions” in light of pre- and post-September 11th knowledge about terrorist risk.

 

Reference book Homeland Security 2nd edition

 
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Case Study

Below are two case study due by Saturday. I need 2 copies of each case study. It should be done in APA format. I have attached the sample APA format document.

RR Communication Case Study

Read the RR Communications Case Study on pages 156-159 in the textbook. Answer Discussion Questions 1-3 at the end of the Case Study. Your responses must be complete, detailed and in APA format. See the sample assignment for expected format and length. The grading rubric is included below. 4-5 pages

Textbook: https://www.studypool.com/uploads/questions/273853/20171015084849it_strategy_issues_and_practice___james_d._mckeen__1_.pdf

Natonstate Insurance Case Study

Read the Nationstate Case Study on pages 160-164 in the textbook. Answer Discussion Questions 1-2 at the end of the Case Study. Your responses must be complete, detailed and in APA format. See the sample assignment for expected format and length. The grading rubric is included below. 4-5 pages

Textbook: https://www.studypool.com/uploads/questions/273853/20171015084849it_strategy_issues_and_practice___james_d._mckeen__1_.pdf

 
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Anthropology Genetic Reproducing Life

Genetics: Reproducing Life and Producing Variation

CLARK SPENCER LARSEN

E S S E N T I A L S O F PHYSICAL ANTHROPOLOGY SECOND EDITION

CHAPTER

3

 

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Copyright ©2013 W.W. Norton, Inc.

Genetics: Reproducing Life and Producing Variation

  • Questions addressed in this chapter:
  • What is the genetic code?
  • What does the genetic code (DNA) do?
  • How does understanding genes help us understand variation?

The last chapter ended with a brief introduction to DNA. But, what is DNA? What is it made of? And how can a small molecule like DNA ‘code’ for all of the traits in a living organism? We will address these and other questions in this chapter. Ultimately, what we are doing in this chapter is understanding how the genetic code (DNA) results in variation, because it is this variation that natural selection can act upon and lead to evolutionary changes. We will start by looking at the fundamental unit of all life on Earth: the cell. Inside each cell, the DNA code is structured into packages known as chromosomes. We will see how the DNA molecule can copy itself so that each cell in an organism’s body contains the same DNA information. We will then look at how DNA codes for proteins, which all living organisms are made of. Finally, we will look at a concrete example of how DNA impacts our lives by examining human blood types. Though we have to dive into the microscopic world, do not lose sight of the big picture: DNA is a code for making proteins, and we are made of proteins. If the DNA slightly changes (through mutation, which we met in the last chapter), the protein changes, and thus the organism can change.

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Copyright ©2013 W.W. Norton, Inc.

The Cell: Prokaryotes

  • Prokaryotes
  • 3.5 billion years old
  • Single-celled bacteria
  • No nucleus or organelles

All living organisms are made of cells; they are the basic units of life. There are many, many organisms that are made of just one cell, and many (including you) that are made of trillions of cells. All of life can be divided into two big categories, depending on the kind of cell they have. The first kind are organisms called prokaryotes. Prokaryotes are single-celled bacteria without nuclei or any special structures called organelles. They often have structures shown here in this image, like a cell wall, an outer membrane, a cytoplasm within which the DNA resides, and they often have locomotor structures like a flagellum. On this slide is a microscopic image of a prokaryotic cell that we have all heard of: Escherichia coli (E. coli), which lives in the guts of many mammals, including humans. Though prokaryotic cells live within us, and have been instrumental factors in driving human evolution, we will turn now to the cells we are made of: eukaryotic cells.

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Copyright ©2013 W.W. Norton, Inc.

The Cell: Eukaryotes

    • Eukaryotes
    • 1.2 billion years ago.
    • Some single-celled; all multicellular organisms (including humans)
    • DNA contained in a nucleus
    • Organelles

 

All animals, plants, fungi, and many single-celled organisms called protists are made of eukaryotic cells. These cells have a nucleus that contains DNA, and often have membrane-bound parts of the cell called organelles. These include chloroplasts (found in plants) and mitochondria, which help produce the molecular energy that powers cellular processes. Notice in this image that the eukaryotic cell is a bit more complicated than a prokaryotic cell. The microscopic image here is of kidney cells, which clearly have a nucleus, a membrane keeping the components of the cell contained, and a fluid within the cell called a cytoplasm.

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Copyright ©2013 W.W. Norton, Inc.

The Cell: Somatic Cells and Gametes

  • Somatic cells
  • Body cells
  • Full DNA (humans: 46 chromosomes)
  • Mitosis
  • Gametes
  • Eggs (ova) and sperm
  • Half DNA (humans; 23 chromosomes)
  • Meiosis

There are two types of eukaryotic cells in all animals and plants: somatic cells and gametes. Somatic cells, also called body cells, are found all over the body. Shown in the above image are the somatic cells found in the (clockwise from top left) brain, blood, bone, and skin. Somatic cells all contain a complete copy of the organism’s DNA. For example, in humans, somatic cells have all of the DNA packed in 46 chromosomes. Somatic cells also replicate through a process called mitosis, which we will learn about in just a moment. At the bottom right is an image of the other kind of eukaryotic cells: gametes. The large round cell is called an egg, or an ova. The small wiggly structures surrounding the egg are sperm. These are gametes. They contain only half of the organism’s DNA (23 chromosomes in humans) and replicate through a process known as meiosis.

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Copyright ©2013 W.W. Norton, Inc.

Chromosomes

  • DNA packaged in chromosomes
  • Chromosome number varies by species
  • Number of chromosomes does not correlate with complexity

Since we just mentioned chromosomes, it is worth examining chromosome number in a bit more detail. Humans have 46 chromosomes in our somatic cells. 23 of these came from our mother, and 23 from our father, for a grand total of 46. But, this number, 46, is not special at all. Other apes, like chimpanzees, have 48 chromosomes. Some primates have fewer chromosomes, like the colobus monkey which has 44. Some organisms we would consider to be less complex than us have fewer chromosomes, like the house fly with 12 or the salamander with 24. But, plenty of organisms have more than we have, like the potato with 48, the camel with 70, or algae, which has 148 chromosomes. Classifying organisms by the number of chromosomes they have would be like organizing books in a library based on the number of pages they have, or by the color of its jacket cover. It wouldn’t make sense. What matters are not the number of chromosomes an organism has, but the similarity in DNA that is packaged in the chromosomes. For instance, humans and chimpanzees share about 98% of their DNA. This is remarkable, and, in some ways, indicates how important 2% of a difference can be.

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Copyright ©2013 W.W. Norton, Inc.

DNA: The Blueprint of Life

• DNA

Genes

Chromosomes

Genome

• Nuclear DNA:

homoplasmic

• Mitochondrial DNA:

heteroplasmic

Most likely, you have all heard of DNA, and have probably heard that it is the “blueprint,” or “recipe,” or “code” for life? But, how does this work? It helps first to understand the structure of DNA, and to understand how it is packaged in your cells. It is estimated that there is six feet worth of DNA in every cell in your body. Six feet!? If cells are microscopic, how can this be? As shown in this image, the DNA molecule is wound up into compact structures that we have already encountered: chromosomes. Sections of that DNA specifically code for a specific protein in the body: These are called genes. The genome is all of the genes put together in all of the chromosomes. The DNA that is in the nucleus of our cells is called homoplasmic, meaning it is more or less the exact same in every cell in our body. But, the nucleus is not the only place in a cell that contains DNA. An organelle called the mitochondria also contains DNA. Mitochondrial DNA (mtDNA) is much, much smaller; it only contains 37 genes. And these genes are only inherited from your mother, meaning they can be used to trace one’s maternal lineage (called a matriline). Unlike nuclear DNA, mitochondrial DNA can differ from cell to cell, making it heteroplasmic.

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Copyright ©2013 W.W. Norton, Inc.

DNA: The Blueprint of Life

  • DNA structure
  • Sugar
  • Phosphate
  • Nucleotide base
  • Adenine (A)
  • Thymine (T)
  • Guanine (G)
  • Cytosine (C)
  • A with T
  • C with G
  • CAAAT
  • GTTTA

 

We are finally ready to discuss what DNA actually is. It is a molecule; in fact, a very simple one. DNA is made of three things: a type of sugar, a phosphate group, and a nucleotide base pair. The sugar and phosphate form the backbone of the long DNA molecule and these do not vary along the chain. What varies along the chain are the nucleotide base pairs. These bases can be one of four types: adenine (A), thymine (T), guanine (G) and cytosine (C). You can think of DNA as a ladder with the sugar and phosphates forming the uprights, and the bases forming the rungs. The rungs are made of two base pairs that cling together using hydrogen bonds. Critical to understanding DNA is the fact that the base pairs do not randomly cling to each other. Instead, A only clings to T, and C only clings to G. These are called complementary bases. What this means is, if you know one side of the DNA chain, you know the other. If a DNA sequence is CAAAT, the other side MUST be GTTTA. Though any two humans may have over 99% of their DNA base pair order identical, there are, of course, differences. Differences in these single nucleotide regions are called SNPs (pronounced “snips” and short for single nucleotide polymorphisms). These are some of the areas of the genome that can be used to solve crimes using DNA evidence since they can vary from one individual to another.

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Copyright ©2013 W.W. Norton, Inc.

The DNA Molecule: Replicating the Code

The very structure of DNA explains how it is so easily, and so accurately, replicated. When a cell is going to divide, it copies its entire genome. Remember those nucleotide base pairs? Well, there are 3 billion of them to copy each time a cell divides. And cells divide all the time. It happened when you went from a single fertilized zygote to two cells, to four, eight, sixteen and onwards until you were several trillion cells worth of newborn baby. It continues to happen as old cells divide to form replacement cells. Each time, the DNA faithfully replicates. DNA replicates so easily and accurately because of those As, Gs, Cs, and Ts we discussed a moment ago. A double stranded DNA molecule is unwound by enzymes, and the hydrogen bonds connecting the complementary base pairs are broken. What results are two template strands that have so-called sticky ends. Free floating nucleotide base pairs in the nucleus of the cell (which are acquired through the foods we eat- which have their own DNA), bind to the template strands following the rule of base pairs: A goes with T and C goes with G. In this case CTAT is separated from GATA. These sticky ends become templates to form two new strands that are identical to one another. Again, it is the very structure of DNA that explains how copies of it can be made. We often say that the replication process produces identical copies of DNA, but that is not entirely true. Copying mistakes can occasionally occur- yet another source for genetic variation.

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Copyright ©2013 W.W. Norton, Inc.

Chromosome Types

  • Homologous pairs
  • Autosomes (22 pairs)
  • Sex chromosomes (1 pair)
  • X and Y
  • Male determines sex
  • Karyotype

 

Before we get into the nuts and bolts of mitosis, let’s consider those chromosomes one last time. In order to make sure that each copy of the full sequence of DNA gets into each cell, the chromosomes must pair up and replicate. 23 of these chromosomes were inherited from the mother, and 23 from the father and each chromosome number (1 to 23) are different in their length and the genes they contain. These chromosomes pair up into matching, or homologous pairings, in the somatic cells. Though these chromosome pairs (shown in the top image) may look identical, they may very well contain different versions of a gene (known as alleles), since one chromosome was inherited from the mother and the other from the father. 22 of the 23 homologous pairs of chromosomes are what are referred to as autosomes. The other pair determines the sex of the individual and are appropriately named the sex chromosomes X and Y. Females have two X chromosomes, one inherited from their mother and one from their father. Males have an X and a Y—the X from their mother and the Y from their father. Because females have two X chromosomes, they can only contribute an X in the egg cell they produce. Because the male has both an X and a Y, there is a 50-50 chance that a sperm will contain an X or a Y. It is therefore true that the male “determines” the sex of a child by either contributing an X (and therefore producing a female) or a Y (and therefore producing a male), though of course this is not a conscious decision the sperm cells make. One way to visualize the homologous chromosomes is to produce what is called a karyotype—this is shown in the bottom right of the slide. Notice the 22 homologous pairs of autosomes numbered according to their size, and last the sex chromosomes. Based on what you see here, is this karyotype from a female or a male?

 

LET THE STUDENTS THINK ABOUT THIS AND THEN DISCUSS (THIS IS A FEMALE KARYOTYPE SINCE THERE ARE TWO X CHROMOSOMES)

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Copyright ©2013 W.W. Norton, Inc.

Mitosis

You started as a single fertilized egg, called a zygote. It had 46 chromosomes. Cells with this full set of chromosomes (46) are called diploid. As we’ll soon see, cells with half the number of chromosomes (23) are called haploid. These are the egg and sperm cells, and there is a very obvious reason that they have half the number of chromosomes, which we’ll encounter in just a moment. But, back to that zygote. During embryological development, this little zygote divided to form 2, 4, 8, 16, 32, 64, and eventually trillions of cells. These cells soon form tissues and organs in a process known as embryological development. If the DNA divided as the cells do, your chromosomes would go from 46 to 23 to 11.5 to 5.75. Of course, this did not happen. Instead, every cell contains 46 chromosomes. This occurs because, as we already discussed, DNA can replicate itself and does so before each cell division so that the cell goes from 46 chromosome to 92 before dividing into two cells, each with 46 chromosomes. The process by which this occurs is called mitosis.

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Copyright ©2013 W.W. Norton, Inc.

Mitosis

As shown in this figure, mitosis starts with a single diploid cell that has 23 pairs or homologous chromosomes (or 46 chromosomes). These chromosomes duplicate by unwinding their DNA and attaching free nucleotide bases to the template strands in the manner already discussed. After chromosome duplication, the cells technically have 92 chromosomes, which all line up in the middle of the cells so that one full set is on one side and another full set is on the other side of the cell midline. The cell pulls apart into two daughter cells, each with identical DNA. The microscopic image is of skin cells dividing into two daughter cells. Each of these cells has 23 pairs of homologous chromosomes (or 46 total).

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Copyright ©2013 W.W. Norton, Inc.

Meiosis

  • Haploid—23 chromosomes (no pairs)
  • Recombination via crossing-over
  • Haplotypes

Translocations and nondisjunctions

 

If an egg cell had 46 chromosomes and a sperm had 46 chromosomes, the resulting zygote would have 92 chromosomes. This simply would not work. So, gametes have to divide up the DNA a bit differently than somatic cells do. Instead of having a full copy of the organism’s DNA, gametes are haploid, meaning they only contain one chromosome from each pair of chromosomes. This one can be inherited from the mother or the one inherited from the father. With 23 chromosomes, the number of different combinations is exceptionally high, meaning that each egg and each sperm cell contains a unique combination of genes from the organisms’ mother and father. The process by which this occurs is called meiosis. Meiosis starts the same way as mitosis. The DNA replicates and the homologous chromosomes pair up. The cells then divide into two identical daughter cells, just as happens in mitosis. However, unlike mitosis, the cells then divide again, resulting in four daughter cells each with 23 chromosomes, but no pairs. Right before that final cell division, the homologous chromosomes can recombine their chromosomes in a process called crossing-over. A chunk of chromosome 2 from the mother’s line can switch with a chunk of chromosome 2 from the father’s line. So, not only are the 23 chromosomes in the gametes a random assortment of chromosomes from the mother and from the father, but within each chromosome there will be a combination of genes from the individual’s mother and father. Genes that are close together on a chromosome therefore tend to move together and cluster together. These clusters of genes are called haplotypes, which can be used to assess the history of genetic lineages. If chunks of DNA are exchanged on non-homologous chromosomes (called translocations) diseases such as leukemia can result. If the chromosomes fail to divide, the resulting gametes can have too few or too many chromosomes. Too few can result in a monosomy, and too many, a trisomy. Down syndrome is an example of a trisomy, in which there are three rather than two copies of chromosome 21.

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Copyright ©2013 W.W. Norton, Inc.

Law of Independent Assortment

We’ve obviously been learning about genetics. But, in the last chapter, we learned about Mendel and his genetics experiments on pea plants. What do the two have to do with each other? This is a very important slide that demonstrates how these concepts are linked to one another. Here is another Punnett square in which two pea plants with identical genotypes and phenotypes are crossed. Each plant has yellow seeds in a green pod, and each plant is heterozygous. Remember that this means that both plants have each allele for pod color and seed color, but that the dominant allele is expressed. Breeding identical plants together like this, most would expect that the offspring should be identical to their parents, but genetics does not work that way. During meiosis, the top pea plant will produce a gamete with either big G or little g combined with either big Y or little y. Each has an equal chance of being produced resulting in four possible combinations of genes in the gametes: GY, Gy, gY, and gy. The same applies for the plant on the left of the Punnett square. Now, when these gametes are combined together in all possible ways to produce zygotes, the resulting baby plants will have the genotypes shown on the Punnett square, and a 9:3:3:1 ratio of phenotypes. Nine will have green pods and yellow seeds like the parents, three will have green pods and green seeds, three will have yellow pods and yellow seeds, and one will have yellow pods and green seeds (the exact OPPOSITE of what the parents had!). Notice that having one particular color of pea pod had nothing to do with the color of the seed. This is known as the law of independent assortment. Notice also that the rules of genetics and the process of meiosis produces plentiful variation—the raw material for natural selection to act on.

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Copyright ©2013 W.W. Norton, Inc.

Law of Independent Assortment

But, those are pea plants. What about humans? Here is an example that applies more to you and I. Suppose the gene for hair color is on the small chromosome and the gene for eye color is on the large chromosome. The blue allele on the small chromosome represents blond hair and on the large chromosome represents blue eyes. The red allele on the small chromosome represents brown hair and on the large chromosome brown eyes. Both parents are heterozygous and, we’ll say for argument sake, brown eyes and hair are dominant, meaning that both parents have brown hair and brown eyes. The parent on the left, we’ll call a female, produces four eggs through meiosis. Because of the law of independent assortment, the alleles for hair and eye color are independent from one another, producing two eggs that pass on the alleles for brown hair and brown eyes and two eggs with the alleles for blond hair and blue eyes. Just as likely is what happens with the male. He produces four sperm cells, two with brown eyes and blond hair and two with blue eyes and brown hair. Choose one egg and one sperm and combine them together. What do you get? Now choose another? Notice that there will be a mixture of these features. Some of the offspring will have blond hair and brown eyes; some will have brown hair and blue eyes. Keep in mind that these combinations were not present in the parents.

Some of you may be saying that hair color and eye color are NOT independent; that they do seem to be present together (brown with brown; blond with blue). You are of course right. One of the reasons for this is that some of the genes that code for these traits are in fact on the same chromosome. The bottom image shows how genes close to one another on the same chromosome will not follow the law of independent assortment and will instead by linked to one another. This is called linkage.

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Copyright ©2013 W.W. Norton, Inc.

DNA and Protein Synthesis

But, how does DNA cause a seed to be yellow or hair to be brown? When we talk about DNA as a code, what do we actually mean? Besides replicating itself, the other critically important thing DNA does is to code for proteins. Proteins are what bodies are made of. There are seven types of proteins described here. Some, called enzymes, help with chemical reactions, such as the protein lactase that helps break down the lactose sugar in milk. Others are structural proteins, like the keratin that makes up our hair and nails, or the collagen that helps make up bone—these are shown in this image to the right. There are gas transport proteins like hemoglobin, which transports oxygen throughout the body. Antibodies, which help fight diseases, are proteins. Hormones like insulin, which helps regulate the metabolism of sugar and fats in the body are proteins. Muscles are comprised of the mechanical proteins actin and myosin. Finally, protein can be of the nutrient-form, like ovalbumin, which is found in egg whites. Proteins are critical for the normal functioning of an organism. So, how does DNA code for these proteins? First, it is important to recognize that proteins are made of amino acids. There are 20 different kinds of amino acids; 12 of these humans can manufacture; the other 8 have to be eaten and are therefore called essential amino acids. These 20 different amino acids can combine together into chains of various lengths and different properties. These properties are what makes a protein like keratin different from a protein like hemoglobin.

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Copyright ©2013 W.W. Norton, Inc.

Transcription and Translation

  • Transcription
  • DNA transcribed into mRNA in the nucleus of the cell
  • Translation
  • mRNA translated into amino acid chain at the ribosomes

Protein synthesis, or the process by which a DNA code is turned into a chain of amino acids, occurs in cells. First the DNA code is read by enzymes, producing a molecule called messenger RNA. This process, in which messenger RNA is created from a DNA code is called transcription. The messenger RNA then leaves the nucleus of the cell and enters the cytoplasm. It binds to ribosomes, which are organelles that facilitate the translation of messenger RNA into a chain of amino acids, which ultimately form a protein. Let’s look in more detail how this actually happens.

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Copyright ©2013 W.W. Norton, Inc.

Transcription

Just like during DNA replication, the DNA is unwound, or unzipped, by enzymes. However, unlike replication, only one of the strands of DNA is used during transcription. Also, unlike replication, only a specific section of the DNA is unwound; this region is called a gene. The unwound DNA strand serves as a template for making a single-stranded molecule of messenger RNA. RNA is very similar to DNA, but instead of using A, G, C, and T as base pairs, RNA uses A, G, C, and U. U stands for Uracil and it binds to adenine (A), just like thymine (T) does in DNA. As is shown here, if the gene has the sequence TACTC, the messenger RNA molecule will be AUGAG and so on. Once the gene is fully transcribed, the messenger RNA molecule leaves the nucleus and finds ribosomes in the cytoplasm of the cell.

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Copyright ©2013 W.W. Norton, Inc.

Translation

Once messenger RNA binds to a ribosome, translation of the code into amino acids can begin. This process occurs in threes. Three nucleotides, called a codon, are read by the ribosome. These are “read” by matching a complementary anticodon to the codon. For instance, if the messenger RNA codon is AUG, then the anticodon has to be UAC since those are the three nucleotides that are complementary to the codon. Importantly, these anticodons are attached to a specific amino acid, in this case methionine, in a structure called a transfer RNA (tRNA). The next three nucleotides in the codon are AGU, which match with the anticodon UCA, which is attached to the amino acid serine. This goes on and one, in groups of three, until the last codon (UAG) , which is the stop sequence. The amino acid chain is then released into the cytoplasm. The amino acid chain folds into a three-dimensional structure, or bonds with other 3-D proteins, which give these proteins their specific properties. What we have described here happens in only a small percentage of the human genome. In fact, only about 5% of the total genome is composed of structural genes that code for proteins, or regulatory genes that turn genes on and off. We will turn to these genes next.

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Copyright ©2013 W.W. Norton, Inc.

Regulatory Genes

  • On/off switches for genes
  • Marfan syndrome
  • Chicken teeth
  • Human hair
  • Lactose intolerance or persistence

Regulatory genes can be thought of as on/off switches, or, perhaps more accurately, dimmer switches. Regulatory genes determine if a gene is on or off, and can regulate the amount of protein produced, and when. For instance, if the genes controlling connective tissue growth are left on a bit longer during development, what can result are longer, thinner fingers as is shown in this image. This is characteristic of a disease called Marfan syndrome. Regulatory genes have also allowed us to understand major evolutionary events. For instance, paleontological evidence demonstrates that modern birds evolved from a group of feathered dinosaurs. But, anyone who has visited a science museum knows that dinosaurs have teeth. Birds do not. Where did their teeth go? Scientists have recently discovered that birds still have the structural genes to make teeth. But, the regulatory genes controlling those structural genes have been turned off. A similar thing has happened with human body hair. Humans have less body hair than other primates. We still have the genes for full body hair coverage, but these genes have been down-regulated. Similarly, all baby mammals have the ability to digest milk. This is because they produce the enzyme lactase, which breaks down lactose. However, these genes are turned off in most adult mammals. However, some humans have lactose persistence, meaning that the genes are not turned off and they can continue to digest milk as adults. Those who retain the typical mammalian condition of losing lactase production into adulthood are said to be lactose intolerant. Notice that natural selection can act upon the products of structural genes, but can also operate on the products of variation in regulatory genes. In fact, research on human and chimpanzee genomes have discovered that while our structural genes are very similar, there are important differences in those regulatory genes.

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Copyright ©2013 W.W. Norton, Inc.

Homeotic (Hox) Genes

One of the best examples of regulatory genes are those of the homeotic, or Hox, family of genes. These are master switches that determine the general form of an animal’s body. Notice that whether you are a human, a mouse, or a fruit fly, heads are where heads should be, bodies are where bodies should be, and limbs are where limbs should be. Why is this? Researchers have discovered that a group of genes, called Hox genes, regulate the position of the major body parts during embryological development. What was amazing to researchers was that the very same genes regulate this process of body formation in organisms as different as flies, mice, and humans. Small changes in how long these genes are switched on, or where they are expressed, can result in differences in overall body form. For instance, the genes for the neck region are positioned differently in birds and snakes giving bird long necks and snakes short necks (but long bodies). The Hox genes that determine forelimb and finger length are switched on for a longer period of development in bats, compared to other mammals. Again, selection can favor the products of variation in regulatory genes as effectively as structural genes.

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Copyright ©2013 W.W. Norton, Inc.

Law of Segregation and Codominance

Let’s look at one more Punnett square to consider how variations in specific genes can result in even more possible combinations of traits. As we have already discussed, the mother and father contribute equally to the genetic makeup of the offspring. This is known as the Law of segregation. Consider this example in which a pure red sweet pea is crossed with a pure white sweet pea. The offspring in the first generation will all be heterozygous, meaning that they will inherit the red allele from one parent and the white allele from the other. If the resulting flowers are all red, then the red allele is said to be dominant over the white allele. But, what if the flowers are all pink? This can happen, it means that these two alleles are both expressed, neither is dominant over the other, and they are said to be codominant. If these flowers care crossed, the offspring will be a combination of pure red (genotype big R big R), pure white (genotype little r little r), and pink, or shown here as hybrid white.

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Copyright ©2013 W.W. Norton, Inc.

Polymorphisms: Variations in Specific Genes

  • Exercises:
  • Can mother with blood type A and father with blood type B have a baby with blood type O?
  • Can a man with blood type AB be the father of a baby with blood type O?

Let’s apply these principles to humans again. Human blood type is a great example of a trait with multiple alleles. A person can be blood type O, A, B, or AB. Because there can be more than one kind of blood type, this is referred to as a polymorphic trait. But, what do these blood types mean in terms of genetics? Every person has two blood type alleles (one from mom and one from dad). These can be allele A, B, or O. The A allele codes for a protein that we call A. The B allele codes for a protein that we call B. If someone has the A allele on one chromosome and the B allele on the other, they are blood type AB. This is because these alleles are codominant and both blood proteins are produced. So, do people with the O allele make an O protein? No. In fact, they do not make a protein at all. This is why the O blood type is referred to as the universal donor. Because there are no proteins on the surface of the cells, the recipient of this blood type will not attack these cells. Someone with blood type AB does not make antibodies against either A or B, and therefore can receive blood from any blood type. However, someone with blood type A will make antibodies against B and cannot receive that blood type without fatal complications. Likewise, someone with blood type O makes antibodies against all other blood types, and cannot receive any other blood type except O. Let’s look at this again in the context of genetics. Can parents with blood type A and blood type B have a baby with blood type O? The answer is yes. Draw a Punnett square to try to work this out. Can either of the parents be homozygous, or must they both be heterozygous? Try this one: Can a man with blood type AB be the father of a child with blood type O? Why or why not?

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Copyright ©2013 W.W. Norton, Inc.

Polygenic Traits and Pleiotropy

  • Many traits polygenic
  • Height, skin color
  • Many genes pleiotropic
  • Sickle-cell
  • All traits a product of genes AND environment
  • Height and nutrition

By this point, you are probably realizing that genetics is complicated business. But, it is MUCH more complicated than I’ve described in this lecture. Many traits are polygenic, meaning that multiple genes are responsible for the phenotype observed. For instance, a person’s height, or skin coloration can be influenced by hundreds of different genes. In addition, these and many other traits can be highly influenced by the environment. For instance, height can be strongly impacted by nutrition. Remember that natural selection can only work on traits that are passed from generation to generation, so quantifying the role that genetics has in shaping a particular phenotype can be quite important in determining the role of natural selection in shaping it. Complicating matters even further is the reality that the same gene can influence many different phenotypes. The sickle-cell gene, for instance, influences both the individual’s ability to combat malaria as well as the ability to transport oxygen through the body. It turns out, most traits are both polygenic and pleiotropic (modeled on the bottom right), making genetics a fascinating, but quite complicated, science.

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Copyright ©2013 W.W. Norton, Inc.

 

 

Genetics: Reproducing

Life and Producing Variation

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Clark • Spencer • Larsen

Essentials of Physical Anthropology

Second Edition

CHAPTER

This concludes the Lecture PowerPoint presentation for:

3

For more learning resources, please visit the
StudySpace site for Essentials of Physical Anthropology
http://books.wwnorton.com/studyspace

 

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The last chapter ended with a brief introduction to DNA. But, what is DNA? What is it made of? And how can a small molecule like DNA ‘code’ for all of the traits in a living organism? We will address these and other questions in this chapter. Ultimately, what we are doing in this chapter is understanding how the genetic code (DNA) results in variation, because it is this variation that natural selection can act upon and lead to evolutionary changes. We will start by looking at the fundamental unit of all life on Earth: the cell. Inside each cell, the DNA code is structured into packages known as chromosomes. We will see how the DNA molecule can copy itself so that each cell in an organism’s body contains the same DNA information. We will then look at how DNA codes for proteins, which all living organisms are made of. Finally, we will look at a concrete example of how DNA impacts our lives by examining human blood types. Though we have to dive into the microscopic world, do not lose sight of the big picture: DNA is a code for making proteins, and we are made of proteins. If the DNA slightly changes (through mutation, which we met in the last chapter), the protein changes, and thus the organism can change.

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All living organisms are made of cells; they are the basic units of life. There are many, many organisms that are made of just one cell, and many (including you) that are made of trillions of cells. All of life can be divided into two big categories, depending on the kind of cell they have. The first kind are organisms called prokaryotes. Prokaryotes are single-celled bacteria without nuclei or any special structures called organelles. They often have structures shown here in this image, like a cell wall, an outer membrane, a cytoplasm within which the DNA resides, and they often have locomotor structures like a flagellum. On this slide is a microscopic image of a prokaryotic cell that we have all heard of: Escherichia coli (E. coli), which lives in the guts of many mammals, including humans. Though prokaryotic cells live within us, and have been instrumental factors in driving human evolution, we will turn now to the cells we are made of: eukaryotic cells.

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All animals, plants, fungi, and many single-celled organisms called protists are made of eukaryotic cells. These cells have a nucleus that contains DNA, and often have membrane-bound parts of the cell called organelles. These include chloroplasts (found in plants) and mitochondria, which help produce the molecular energy that powers cellular processes. Notice in this image that the eukaryotic cell is a bit more complicated than a prokaryotic cell. The microscopic image here is of kidney cells, which clearly have a nucleus, a membrane keeping the components of the cell contained, and a fluid within the cell called a cytoplasm.

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There are two types of eukaryotic cells in all animals and plants: somatic cells and gametes. Somatic cells, also called body cells, are found all over the body. Shown in the above image are the somatic cells found in the (clockwise from top left) brain, blood, bone, and skin. Somatic cells all contain a complete copy of the organism’s DNA. For example, in humans, somatic cells have all of the DNA packed in 46 chromosomes. Somatic cells also replicate through a process called mitosis, which we will learn about in just a moment. At the bottom right is an image of the other kind of eukaryotic cells: gametes. The large round cell is called an egg, or an ova. The small wiggly structures surrounding the egg are sperm. These are gametes. They contain only half of the organism’s DNA (23 chromosomes in humans) and replicate through a process known as meiosis.

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Since we just mentioned chromosomes, it is worth examining chromosome number in a bit more detail. Humans have 46 chromosomes in our somatic cells. 23 of these came from our mother, and 23 from our father, for a grand total of 46. But, this number, 46, is not special at all. Other apes, like chimpanzees, have 48 chromosomes. Some primates have fewer chromosomes, like the colobus monkey which has 44. Some organisms we would consider to be less complex than us have fewer chromosomes, like the house fly with 12 or the salamander with 24. But, plenty of organisms have more than we have, like the potato with 48, the camel with 70, or algae, which has 148 chromosomes. Classifying organisms by the number of chromosomes they have would be like organizing books in a library based on the number of pages they have, or by the color of its jacket cover. It wouldn’t make sense. What matters are not the number of chromosomes an organism has, but the similarity in DNA that is packaged in the chromosomes. For instance, humans and chimpanzees share about 98% of their DNA. This is remarkable, and, in some ways, indicates how important 2% of a difference can be.

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Most likely, you have all heard of DNA, and have probably heard that it is the “blueprint,” or “recipe,” or “code” for life? But, how does this work? It helps first to understand the structure of DNA, and to understand how it is packaged in your cells. It is estimated that there is six feet worth of DNA in every cell in your body. Six feet!? If cells are microscopic, how can this be? As shown in this image, the DNA molecule is wound up into compact structures that we have already encountered: chromosomes. Sections of that DNA specifically code for a specific protein in the body: These are called genes. The genome is all of the genes put together in all of the chromosomes. The DNA that is in the nucleus of our cells is called homoplasmic, meaning it is more or less the exact same in every cell in our body. But, the nucleus is not the only place in a cell that contains DNA. An organelle called the mitochondria also contains DNA. Mitochondrial DNA (mtDNA) is much, much smaller; it only contains 37 genes. And these genes are only inherited from your mother, meaning they can be used to trace one’s maternal lineage (called a matriline). Unlike nuclear DNA, mitochondrial DNA can differ from cell to cell, making it heteroplasmic.

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We are finally ready to discuss what DNA actually is. It is a molecule; in fact, a very simple one. DNA is made of three things: a type of sugar, a phosphate group, and a nucleotide base pair. The sugar and phosphate form the backbone of the long DNA molecule and these do not vary along the chain. What varies along the chain are the nucleotide base pairs. These bases can be one of four types: adenine (A), thymine (T), guanine (G) and cytosine (C). You can think of DNA as a ladder with the sugar and phosphates forming the uprights, and the bases forming the rungs. The rungs are made of two base pairs that cling together using hydrogen bonds. Critical to understanding DNA is the fact that the base pairs do not randomly cling to each other. Instead, A only clings to T, and C only clings to G. These are called complementary bases. What this means is, if you know one side of the DNA chain, you know the other. If a DNA sequence is CAAAT, the other side MUST be GTTTA. Though any two humans may have over 99% of their DNA base pair order identical, there are, of course, differences. Differences in these single nucleotide regions are called SNPs (pronounced “snips” and short for single nucleotide polymorphisms). These are some of the areas of the genome that can be used to solve crimes using DNA evidence since they can vary from one individual to another.

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The very structure of DNA explains how it is so easily, and so accurately, replicated. When a cell is going to divide, it copies its entire genome. Remember those nucleotide base pairs? Well, there are 3 billion of them to copy each time a cell divides. And cells divide all the time. It happened when you went from a single fertilized zygote to two cells, to four, eight, sixteen and onwards until you were several trillion cells worth of newborn baby. It continues to happen as old cells divide to form replacement cells. Each time, the DNA faithfully replicates. DNA replicates so easily and accurately because of those As, Gs, Cs, and Ts we discussed a moment ago. A double stranded DNA molecule is unwound by enzymes, and the hydrogen bonds connecting the complementary base pairs are broken. What results are two template strands that have so-called sticky ends. Free floating nucleotide base pairs in the nucleus of the cell (which are acquired through the foods we eat- which have their own DNA), bind to the template strands following the rule of base pairs: A goes with T and C goes with G. In this case CTAT is separated from GATA. These sticky ends become templates to form two new strands that are identical to one another. Again, it is the very structure of DNA that explains how copies of it can be made. We often say that the replication process produces identical copies of DNA, but that is not entirely true. Copying mistakes can occasionally occur- yet another source for genetic variation.

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Before we get into the nuts and bolts of mitosis, let’s consider those chromosomes one last time. In order to make sure that each copy of the full sequence of DNA gets into each cell, the chromosomes must pair up and replicate. 23 of these chromosomes were inherited from the mother, and 23 from the father and each chromosome number (1 to 23) are different in their length and the genes they contain. These chromosomes pair up into matching, or homologous pairings, in the somatic cells. Though these chromosome pairs (shown in the top image) may look identical, they may very well contain different versions of a gene (known as alleles), since one chromosome was inherited from the mother and the other from the father. 22 of the 23 homologous pairs of chromosomes are what are referred to as autosomes. The other pair determines the sex of the individual and are appropriately named the sex chromosomes X and Y. Females have two X chromosomes, one inherited from their mother and one from their father. Males have an X and a Y—the X from their mother and the Y from their father. Because females have two X chromosomes, they can only contribute an X in the egg cell they produce. Because the male has both an X and a Y, there is a 50-50 chance that a sperm will contain an X or a Y. It is therefore true that the male “determines” the sex of a child by either contributing an X (and therefore producing a female) or a Y (and therefore producing a male), though of course this is not a conscious decision the sperm cells make. One way to visualize the homologous chromosomes is to produce what is called a karyotype—this is shown in the bottom right of the slide. Notice the 22 homologous pairs of autosomes numbered according to their size, and last the sex chromosomes. Based on what you see here, is this karyotype from a female or a male?

 

LET THE STUDENTS THINK ABOUT THIS AND THEN DISCUSS (THIS IS A FEMALE KARYOTYPE SINCE THERE ARE TWO X CHROMOSOMES)

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You started as a single fertilized egg, called a zygote. It had 46 chromosomes. Cells with this full set of chromosomes (46) are called diploid. As we’ll soon see, cells with half the number of chromosomes (23) are called haploid. These are the egg and sperm cells, and there is a very obvious reason that they have half the number of chromosomes, which we’ll encounter in just a moment. But, back to that zygote. During embryological development, this little zygote divided to form 2, 4, 8, 16, 32, 64, and eventually trillions of cells. These cells soon form tissues and organs in a process known as embryological development. If the DNA divided as the cells do, your chromosomes would go from 46 to 23 to 11.5 to 5.75. Of course, this did not happen. Instead, every cell contains 46 chromosomes. This occurs because, as we already discussed, DNA can replicate itself and does so before each cell division so that the cell goes from 46 chromosome to 92 before dividing into two cells, each with 46 chromosomes. The process by which this occurs is called mitosis.

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As shown in this figure, mitosis starts with a single diploid cell that has 23 pairs or homologous chromosomes (or 46 chromosomes). These chromosomes duplicate by unwinding their DNA and attaching free nucleotide bases to the template strands in the manner already discussed. After chromosome duplication, the cells technically have 92 chromosomes, which all line up in the middle of the cells so that one full set is on one side and another full set is on the other side of the cell midline. The cell pulls apart into two daughter cells, each with identical DNA. The microscopic image is of skin cells dividing into two daughter cells. Each of these cells has 23 pairs of homologous chromosomes (or 46 total).

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If an egg cell had 46 chromosomes and a sperm had 46 chromosomes, the resulting zygote would have 92 chromosomes. This simply would not work. So, gametes have to divide up the DNA a bit differently than somatic cells do. Instead of having a full copy of the organism’s DNA, gametes are haploid, meaning they only contain one chromosome from each pair of chromosomes. This one can be inherited from the mother or the one inherited from the father. With 23 chromosomes, the number of different combinations is exceptionally high, meaning that each egg and each sperm cell contains a unique combination of genes from the organisms’ mother and father. The process by which this occurs is called meiosis. Meiosis starts the same way as mitosis. The DNA replicates and the homologous chromosomes pair up. The cells then divide into two identical daughter cells, just as happens in mitosis. However, unlike mitosis, the cells then divide again, resulting in four daughter cells each with 23 chromosomes, but no pairs. Right before that final cell division, the homologous chromosomes can recombine their chromosomes in a process called crossing-over. A chunk of chromosome 2 from the mother’s line can switch with a chunk of chromosome 2 from the father’s line. So, not only are the 23 chromosomes in the gametes a random assortment of chromosomes from the mother and from the father, but within each chromosome there will be a combination of genes from the individual’s mother and father. Genes that are close together on a chromosome therefore tend to move together and cluster together. These clusters of genes are called haplotypes, which can be used to assess the history of genetic lineages. If chunks of DNA are exchanged on non-homologous chromosomes (called translocations) diseases such as leukemia can result. If the chromosomes fail to divide, the resulting gametes can have too few or too many chromosomes. Too few can result in a monosomy, and too many, a trisomy. Down syndrome is an example of a trisomy, in which there are three rather than two copies of chromosome 21.

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We’ve obviously been learning about genetics. But, in the last chapter, we learned about Mendel and his genetics experiments on pea plants. What do the two have to do with each other? This is a very important slide that demonstrates how these concepts are linked to one another. Here is another Punnett square in which two pea plants with identical genotypes and phenotypes are crossed. Each plant has yellow seeds in a green pod, and each plant is heterozygous. Remember that this means that both plants have each allele for pod color and seed color, but that the dominant allele is expressed. Breeding identical plants together like this, most would expect that the offspring should be identical to their parents, but genetics does not work that way. During meiosis, the top pea plant will produce a gamete with either big G or little g combined with either big Y or little y. Each has an equal chance of being produced resulting in four possible combinations of genes in the gametes: GY, Gy, gY, and gy. The same applies for the plant on the left of the Punnett square. Now, when these gametes are combined together in all possible ways to produce zygotes, the resulting baby plants will have the genotypes shown on the Punnett square, and a 9:3:3:1 ratio of phenotypes. Nine will have green pods and yellow seeds like the parents, three will have green pods and green seeds, three will have yellow pods and yellow seeds, and one will have yellow pods and green seeds (the exact OPPOSITE of what the parents had!). Notice that having one particular color of pea pod had nothing to do with the color of the seed. This is known as the law of independent assortment. Notice also that the rules of genetics and the process of meiosis produces plentiful variation—the raw material for natural selection to act on.

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But, those are pea plants. What about humans? Here is an example that applies more to you and I. Suppose the gene for hair color is on the small chromosome and the gene for eye color is on the large chromosome. The blue allele on the small chromosome represents blond hair and on the large chromosome represents blue eyes. The red allele on the small chromosome represents brown hair and on the large chromosome brown eyes. Both parents are heterozygous and, we’ll say for argument sake, brown eyes and hair are dominant, meaning that both parents have brown hair and brown eyes. The parent on the left, we’ll call a female, produces four eggs through meiosis. Because of the law of independent assortment, the alleles for hair and eye color are independent from one another, producing two eggs that pass on the alleles for brown hair and brown eyes and two eggs with the alleles for blond hair and blue eyes. Just as likely is what happens with the male. He produces four sperm cells, two with brown eyes and blond hair and two with blue eyes and brown hair. Choose one egg and one sperm and combine them together. What do you get? Now choose another? Notice that there will be a mixture of these features. Some of the offspring will have blond hair and brown eyes; some will have brown hair and blue eyes. Keep in mind that these combinations were not present in the parents.

Some of you may be saying that hair color and eye color are NOT independent; that they do seem to be present together (brown with brown; blond with blue). You are of course right. One of the reasons for this is that some of the genes that code for these traits are in fact on the same chromosome. The bottom image shows how genes close to one another on the same chromosome will not follow the law of independent assortment and will instead by linked to one another. This is called linkage.

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But, how does DNA cause a seed to be yellow or hair to be brown? When we talk about DNA as a code, what do we actually mean? Besides replicating itself, the other critically important thing DNA does is to code for proteins. Proteins are what bodies are made of. There are seven types of proteins described here. Some, called enzymes, help with chemical reactions, such as the protein lactase that helps break down the lactose sugar in milk. Others are structural proteins, like the keratin that makes up our hair and nails, or the collagen that helps make up bone—these are shown in this image to the right. There are gas transport proteins like hemoglobin, which transports oxygen throughout the body. Antibodies, which help fight diseases, are proteins. Hormones like insulin, which helps regulate the metabolism of sugar and fats in the body are proteins. Muscles are comprised of the mechanical proteins actin and myosin. Finally, protein can be of the nutrient-form, like ovalbumin, which is found in egg whites. Proteins are critical for the normal functioning of an organism. So, how does DNA code for these proteins? First, it is important to recognize that proteins are made of amino acids. There are 20 different kinds of amino acids; 12 of these humans can manufacture; the other 8 have to be eaten and are therefore called essential amino acids. These 20 different amino acids can combine together into chains of various lengths and different properties. These properties are what makes a protein like keratin different from a protein like hemoglobin.

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Protein synthesis, or the process by which a DNA code is turned into a chain of amino acids, occurs in cells. First the DNA code is read by enzymes, producing a molecule called messenger RNA. This process, in which messenger RNA is created from a DNA code is called transcription. The messenger RNA then leaves the nucleus of the cell and enters the cytoplasm. It binds to ribosomes, which are organelles that facilitate the translation of messenger RNA into a chain of amino acids, which ultimately form a protein. Let’s look in more detail how this actually happens.

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Just like during DNA replication, the DNA is unwound, or unzipped, by enzymes. However, unlike replication, only one of the strands of DNA is used during transcription. Also, unlike replication, only a specific section of the DNA is unwound; this region is called a gene. The unwound DNA strand serves as a template for making a single-stranded molecule of messenger RNA. RNA is very similar to DNA, but instead of using A, G, C, and T as base pairs, RNA uses A, G, C, and U. U stands for Uracil and it binds to adenine (A), just like thymine (T) does in DNA. As is shown here, if the gene has the sequence TACTC, the messenger RNA molecule will be AUGAG and so on. Once the gene is fully transcribed, the messenger RNA molecule leaves the nucleus and finds ribosomes in the cytoplasm of the cell.

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Once messenger RNA binds to a ribosome, translation of the code into amino acids can begin. This process occurs in threes. Three nucleotides, called a codon, are read by the ribosome. These are “read” by matching a complementary anticodon to the codon. For instance, if the messenger RNA codon is AUG, then the anticodon has to be UAC since those are the three nucleotides that are complementary to the codon. Importantly, these anticodons are attached to a specific amino acid, in this case methionine, in a structure called a transfer RNA (tRNA). The next three nucleotides in the codon are AGU, which match with the anticodon UCA, which is attached to the amino acid serine. This goes on and one, in groups of three, until the last codon (UAG) , which is the stop sequence. The amino acid chain is then released into the cytoplasm. The amino acid chain folds into a three-dimensional structure, or bonds with other 3-D proteins, which give these proteins their specific properties. What we have described here happens in only a small percentage of the human genome. In fact, only about 5% of the total genome is composed of structural genes that code for proteins, or regulatory genes that turn genes on and off. We will turn to these genes next.

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Regulatory genes can be thought of as on/off switches, or, perhaps more accurately, dimmer switches. Regulatory genes determine if a gene is on or off, and can regulate the amount of protein produced, and when. For instance, if the genes controlling connective tissue growth are left on a bit longer during development, what can result are longer, thinner fingers as is shown in this image. This is characteristic of a disease called Marfan syndrome. Regulatory genes have also allowed us to understand major evolutionary events. For instance, paleontological evidence demonstrates that modern birds evolved from a group of feathered dinosaurs. But, anyone who has visited a science museum knows that dinosaurs have teeth. Birds do not. Where did their teeth go? Scientists have recently discovered that birds still have the structural genes to make teeth. But, the regulatory genes controlling those structural genes have been turned off. A similar thing has happened with human body hair. Humans have less body hair than other primates. We still have the genes for full body hair coverage, but these genes have been down-regulated. Similarly, all baby mammals have the ability to digest milk. This is because they produce the enzyme lactase, which breaks down lactose. However, these genes are turned off in most adult mammals. However, some humans have lactose persistence, meaning that the genes are not turned off and they can continue to digest milk as adults. Those who retain the typical mammalian condition of losing lactase production into adulthood are said to be lactose intolerant. Notice that natural selection can act upon the products of structural genes, but can also operate on the products of variation in regulatory genes. In fact, research on human and chimpanzee genomes have discovered that while our structural genes are very similar, there are important differences in those regulatory genes.

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One of the best examples of regulatory genes are those of the homeotic, or Hox, family of genes. These are master switches that determine the general form of an animal’s body. Notice that whether you are a human, a mouse, or a fruit fly, heads are where heads should be, bodies are where bodies should be, and limbs are where limbs should be. Why is this? Researchers have discovered that a group of genes, called Hox genes, regulate the position of the major body parts during embryological development. What was amazing to researchers was that the very same genes regulate this process of body formation in organisms as different as flies, mice, and humans. Small changes in how long these genes are switched on, or where they are expressed, can result in differences in overall body form. For instance, the genes for the neck region are positioned differently in birds and snakes giving bird long necks and snakes short necks (but long bodies). The Hox genes that determine forelimb and finger length are switched on for a longer period of development in bats, compared to other mammals. Again, selection can favor the products of variation in regulatory genes as effectively as structural genes.

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Let’s look at one more Punnett square to consider how variations in specific genes can result in even more possible combinations of traits. As we have already discussed, the mother and father contribute equally to the genetic makeup of the offspring. This is known as the Law of segregation. Consider this example in which a pure red sweet pea is crossed with a pure white sweet pea. The offspring in the first generation will all be heterozygous, meaning that they will inherit the red allele from one parent and the white allele from the other. If the resulting flowers are all red, then the red allele is said to be dominant over the white allele. But, what if the flowers are all pink? This can happen, it means that these two alleles are both expressed, neither is dominant over the other, and they are said to be codominant. If these flowers care crossed, the offspring will be a combination of pure red (genotype big R big R), pure white (genotype little r little r), and pink, or shown here as hybrid white.

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Let’s apply these principles to humans again. Human blood type is a great example of a trait with multiple alleles. A person can be blood type O, A, B, or AB. Because there can be more than one kind of blood type, this is referred to as a polymorphic trait. But, what do these blood types mean in terms of genetics? Every person has two blood type alleles (one from mom and one from dad). These can be allele A, B, or O. The A allele codes for a protein that we call A. The B allele codes for a protein that we call B. If someone has the A allele on one chromosome and the B allele on the other, they are blood type AB. This is because these alleles are codominant and both blood proteins are produced. So, do people with the O allele make an O protein? No. In fact, they do not make a protein at all. This is why the O blood type is referred to as the universal donor. Because there are no proteins on the surface of the cells, the recipient of this blood type will not attack these cells. Someone with blood type AB does not make antibodies against either A or B, and therefore can receive blood from any blood type. However, someone with blood type A will make antibodies against B and cannot receive that blood type without fatal complications. Likewise, someone with blood type O makes antibodies against all other blood types, and cannot receive any other blood type except O. Let’s look at this again in the context of genetics. Can parents with blood type A and blood type B have a baby with blood type O? The answer is yes. Draw a Punnett square to try to work this out. Can either of the parents be homozygous, or must they both be heterozygous? Try this one: Can a man with blood type AB be the father of a child with blood type O? Why or why not?

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By this point, you are probably realizing that genetics is complicated business. But, it is MUCH more complicated than I’ve described in this lecture. Many traits are polygenic, meaning that multiple genes are responsible for the phenotype observed. For instance, a person’s height, or skin coloration can be influenced by hundreds of different genes. In addition, these and many other traits can be highly influenced by the environment. For instance, height can be strongly impacted by nutrition. Remember that natural selection can only work on traits that are passed from generation to generation, so quantifying the role that genetics has in shaping a particular phenotype can be quite important in determining the role of natural selection in shaping it. Complicating matters even further is the reality that the same gene can influence many different phenotypes. The sickle-cell gene, for instance, influences both the individual’s ability to combat malaria as well as the ability to transport oxygen through the body. It turns out, most traits are both polygenic and pleiotropic (modeled on the bottom right), making genetics a fascinating, but quite complicated, science.

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Go To The Philippines To Study Primates Called Tarsiers! Download The Assignment And Answer Sheet Below.

Anthropology 130 Online Research Simulation 1
Tarsier Research Project
50 points total
Instructions
This research simulation will take you through a fictional example of genetic inheritance. The
textbook and lecture slides on heredity, genetics, biological evolution, and population genetics
should have all of the information that you need to successfully complete the assignment. Use
Internet resources as a last resort since that information is less controlled.
Enter your answers into the Research Simulation 1 Answer Sheet Word document and upload it
to Canvas to turn in.
Assignment Start
Congratulations! You have been accepted into a prestigious research program. You will be
joining a team of primatologists who have started to conduct research on a population of tarsiers
living on an island in the Philippines. (Tarsiers are
hand-sized primates who share a distant common
ancestor with humans but evolved in their own way to
survive in forests). The researchers believe that tarsier
fur color is strongly influenced by their genes, so they
plan to genetically test tarsiers of different colors to see
what their genotypes are like.
Since you’re the newest member of the research team,
the primatologists have given you the work of

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{ Caption: A tarsier. }
preparing the data that they have collected to present to The National Science Foundation. At
least you get to work in the Philippines!
Part One
The international airport is bustling with activity as you wait for your flight to the Philippines.
Announcements in many languages ring out over the speakers. You make a small game of
trying to identify the languages being spoken. Surprisingly, you hear a young voice next to you:
“Hi are you a scientist?”
A child full of curiosity has climbed into the seat next to yours while you were distracted. You
reply to the child that you are indeed a scientist. The child looks up at your with beaming eyes. “I
have a question. In school, we learn about the scientis- scientific method, but I didn’t understand
something. Could you tell me the difference between a hyp- hypo- hypothemesis and a theory?”

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{ Your new workplace (not really). }

1.
Explain to the child the difference between a
hypothesis
and a
theory
in your own way,
based on the book and lecture. Use at least one sentence. (1 point)
2.
The child has you attention for now. Continue by explaining how the process of scientific
research improves our knowledge over time while bad data and theories are discarded. (1
point)
Satisfied, the child climbs off the seat and wanders away. Soon, the gate opens and you board
the plane to your research adventure.
Part Two
By the time you are able to join the team in the Philippines, the researchers have already taken
genetic samples of wild tarsiers. Analyzing their DNA, scientists have isolated a few genotypes,
or the genetic makeup, or a few individuals. The genotypes have been given names following
the standard convention of using capital and lowercase letters to represent different alleles in a
gene.
For each of the following four genotypes, indicate in the answer sheet whether it is
heterozygous
,
homozygous dominant
,
or homozygous recessive
: (1 point total)
3.
Hh
4.
MM
5.
ff

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6.
Make up your own heterozygous genotype, using a letter of your choice (1 point).
Part Three
The scientists noticed that the tarsiers of this particular island came in two varieties of fur color:
brown and silver. These colors are determined by the Fur gene, which has two possible alleles.
Comparing the fur phenotype with the genotype, they found that the uppercase ‘
F
’ allele codes
for brown fur while the lowercase ‘
f
’ allele codes for silver fur.
Based on this information, would the fur color of tarsiers with the following genotype be brown or
silver? (1 point total).

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{ Caption: Photoshopped renditions of the silver and
brown tarsiers for this assignment. Real tarsiers do
have differences in fur color, though!}

7.
Ff
8.
ff
9.
FF
Part Four
Continuing their research, the primatologists temporarily capture a few tarsiers to observe over
a few days. Two of the captive tarsiers, one male and one female, are very fond of each other.
Looking at their DNA, scientists found that one has the genotype
FF
for the fur color gene and
the other tarsier has
ff
as its genotype. One of your fellow researchers, Jherry,  is filling out a
Punnett square to diagram the possible genotypes of any offspring of this tarsier pair. He shows
you his template:
Jherry is eager to demonstrate what he learned when he took ANTH 101 last semester: “You
see, each parent’s genotype is given in the gray squares. With this information, we just move
the alleles for Parent 1 across each row and drop the alleles for Parent 2 down each column to
see how these alleles would combine in their offspring. For this pairing…”

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Parent 2
F
F
Parent
1
f
f
Not to be outdone, you jump in to help Jherry figure out his Punnett square.
10.
What would be each offspring genotype in the four white blanks in the Punnett square? In
the answer sheet write the genotype derived from the parents in each white square. (1 point)
11.
What would be the fur color of all of these offspring, and why? Explain your reasoning with
at least a full sentence. (1 points)
One of the researchers, Lhindsay, comes back excitedly from the forest: “The two parent
tarsiers had a baby!” Being a top tarsier researcher, she already has a sample of the newborn’s
DNA to test. The results show that the offspring with the genotype
Ff
. Lhindsay’s mind reels
from the possibilities of this young tarsier. “What if the
Ff
baby grows up and mates with
another
Ff
tarsier?! What types of offspring are possible?” You work to answer Lhindsay’s question by
making another Punnett square. You start with the parents’ separated alleles in the gray
squares and then work to fill in the four white squares with the offspring’s genotypes:

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Parent 2
Parent
1
12.
What would be in each of the white squares in the answer sheet showing the possible
genotypes of the grandchildren if the baby
Ff
tarsier grew up and mated with another
Ff
tarsier? (1 points)
13.
For each of the genotypes from question #12, what would be the resulting phenotype or
actual fur color? Fill in each the correct phenotype for each white square in the Punnett
Square with either the word ‘
brown
’ or ‘
silver
’ based on the genotype from #12. (1 points)
14.
Based on your results, which phenotype (brown or silver) would be more likely to appear in
the grandchildren? Explain your reasoning in at least a complete sentence, explaining what
you see in your previous answer. (2 points)
“Thank you!” Lhindsay exclaims. She runs off to tell Jherry and the other researchers the good
news, along with your additional information.
Part Five
The researchers are grateful that you have gotten this work done for them so that they can keep
conducting fieldwork in the forest. One day, the researchers find a family of tarsiers with red fur!
A new allele in the fur color gene must have appeared due to a change in the DNA of one of the
tarsiers. This new allele then got passed to the next generation. Lindsay is very excited by this
new discovery: “The red fur allele must have been created the… oh, what is the force of
evolution that is the only source of new alleles?”
15.
Help out Lhindsay: what is the force of biological evolution that is the only source of new
alleles? (1 points)

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Observations of the red fur tarsiers show that
they blend in better with the reddish brown
tree trunks in the environment compared to
both
the brown and silver fur tarsiers. This
means that the red fur tarsiers are less likely
to be caught and eaten by the tarsier-eating
hawks that patrol the forest.
16.
Given the above pattern over many
generations, would the red fur tarsiers be
more or less common compared to the
brown and silver tarsiers? (1 point)
You start documenting these results for the
team, but you need to recall the best vocabulary term to describe what is going on.
17.
The change in fur color trends of the tarsier population, due to each color affecting
reproductive success differently, is an example of which force of evolution? (2 points)
18.
You know that there are tarsiers living on the other side of the river where you found the red
fur tarsiers. Due to the rapid current of the river, the tarsiers on one side rarely meet the
tarsiers on the other. Is this an example of
high
or
low
gene flow between these two
groups? (1 point)

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{ Caption: The newly discovered red tarsier (still
fictional for this assignment!). }

Part Six
After filling in the details of your report, you join the research team to eat dinner and discuss the
findings under the big research tent. Lhindsay and Jherry thank you for being so helpful. The
primary investigator of this team, the P.I., strolls up to you and hands you a celebratory lumpia
(spring roll).
“Excellent work on the tarsier fur colors. The red fur tarsiers will really add to what we know
about this branch of primates, and all primates in general. We still don’t know if the new red fur
allele is dominant or recessive. If it is recessive, like the f allele, then only F will be dominant for
this gene, overriding the other alleles. If it turns out that the red fur allele is as dominant as the
brown fur allele… what is the word for that situation?”
19.
Impress the P.I.: what is the term for a gene where multiple alleles for a gene are dominant?
(1 point)
20.
If the red fur allele is also dominant, what could a tarsier look like if it had both the red allele
and the brown allele? (1 point)
“There is a chance that the fur gene affects more than just the fur color: eye color may be
affected as well! In that case, this one gene affects multiple traits.”
21.
What is the term for a gene that affects more than one trait? (1 point)
“There are so many complications to genetics beyond what we just went over. I know that you
have read the book
Essentials of Physical Anthropology
by Clark Spencer Larsen. He’s a great
professor! Do you recall what the book said about regulatory and structural genes?”

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22.
What is the definition of a regulatory gene? Use a complete sentence and rephrase the
definition from what the book says. (1 point)
23.
What is the definition of a structural gene? Use a complete sentence and rephrase the
definition from what the book says. (1 point)
24.
What is the name for the type of gene found in many different animals that controls the
development of body parts? (1 point)
Your Primary Investigator nods in contentment. “It’s been great chatting with you. I’m very
excited about analyzing these data and adding on to our scientific knowledge. To be honest, I’m
a little competitive. Another research team may discover the same things about tarsiers and
publish their discovery first. It’s like when Charles Darwin was almost too late in publishing his
work on natural selection because another researcher was following the same clues to the
same theory. Now, Darwin is the famous name for natural selection, while the other guy is less
well known. In fact, what was his name? Maybe you read an article about it.”
25.
Who was the researcher who almost announced his discovery of natural selection before
Charles Darwin did it? (1 point)
Part Seven
The next day, you stop by the nearby town of Corella to visit an Internet café and see what is
going on with social media. You received some messages from friends asking about what you
did recently in your research.

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26.
Write a short status message of around 150 words describing what you did and learned
while studying tarsiers as if you were really there. College-level writing is
not
required! Have
fun with it. (2 points)
Conclusion
The eventful field season concluded, you return home from the Philippines to turn in your
answer sheet. The researchers continue their work on finding more about tarsiers. They can
now test the new hypothesis that the red fur will become more common in the future. By careful
observation of the environment, scientists can make and test hypotheses about how the tarsier
genotype and phenotype are interrelated. This adds a little bit of new information to the existing
scientific knowledge. We will learn more about tarsiers later in the course!
Be sure to have answered every question in the answer sheet before submitting it on Canvas.

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11 Caption: The public market in Corella (it’s a real town!).

 
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Who Can’t Do Accounting Work

Mountain Top Hardware Instructions and Guidance

 

Practice set overview

This practice set is a project that reviews and test your comprehension of all the material that you’ve learned in chapters one through six. In this practice set you will be the bookkeeper keeping the books for a company that is both a retailer and a wholesaler. In chapters 1-4 we covered the 10 steps of the accounting cycle. It will be your job to complete all ten of these steps for this company for a period of one month. These steps must be completed in order (you cannot complete step 2 until step 1 is completed and you cannot complete step 3 until step 2 is completed and so on.) The Mountain Top Hardware guidance document will assist you in the process of navigating these ten steps and enlighten you to the percent of your grade you will earn along the way.

The table below shows those ten steps and the percentage of your final grade you can earn on this project as you complete each step. Following the table is an overview of each book in the project and a section that describes in more detail what needs to be done in each of the steps and which books are utilized to complete each of these steps.

Table 1:

 

Table 1: Steps in the Accounting Cycle % of Final Grade
Step 1: Analyzing and recording transactions in the journal 20%
Step 2: Posting transactions to the Ledger 10%
Step 3: Prepare an Unadjusted Trial Balance 10%
Step 4: Assemble and Analyze Adjustment Data (provided for you in book 1 page 2)  
Step 5: Prepare End of Period Spreadsheet (this step is omitted from this project)  
Step 6: Journalize and Post Adjusting Entries (book 1 page 8) 10%
Step 7: Prepare Adjusted Trial Balance 10%
Step 8: Prepare Financial Statements 20%
Step 9: Journalize and Post the Closing Entries (book 1 page 9) 15%
Step 10 Prepare a Post Closing Trial Balance (book 1 page 22) 5%
  100%

 

 

You must complete all 10 steps in order to fulfill the requirements of this project. You will spend a large portion of your efforts completing steps 1 and 2 but that only earns you 30% of your grade. Don’t stop after steps 1 and 2 are complete. The guidance provided below will assist you in the completion of the project.

 

Preparation and Introduction

First take your four books out of the envelope and write your name in ink in the front of each book, you might want to include your phone number or email in case your books get lost . Please do not dispose of the envelope these four booklets came in You will be submitting these four books completed in this envelope . Next in the top left corner of the envelope write YOUR NAME, THE CLASS and SECTION (if you are taking the class as a hybrid your section is H01, H02 or EH1 – if you are taking the class on line your section is N01, N02 or AN1 or AN2), and the SEMESTER and YEAR you are taking the class. For example my envelope would look like this and contain the four books completed :

 

 

Once you are done with those things you need to put your pen away – no more ink can be used in this project. You will make mistakes and you will need to erase. I will not accept any project with ink beyond the stated items above.

Now let’s get familiar with each of the four books.

Book 1:

Open up book one to page 1 there’s a general discussion about what the Mountain Top Hardware business does. Page 1 also list the five journals you will use to record the 50 transaction (provided in book 3 – more about that later). The first journal listed is the “General Journal”. You should be familiar with this journal from chapters 2-4. This is the place where we have recorded (journalize) transactions. The next journals are special journals introduced in chapter 5. We will utilize these journals to simplify recording transactions. These special journals include a “Sales Journal”, “Purchases Journal”, “Cash Receipts Journal”, and “Cash Payments Journal”. All five of these journals are in book 1. This page also list the ledgers that will be utilized in this project. They include the “General Ledger” (chapter 2 in the text) and subsidiary ledgers for accounts receivable and accounts payable (chapter 5) if you need to review their function. Page 1 goes on to explain the chart of accounts and the numbering scheme for the general ledger. The inside cover of book 2 provides the chart of accounts for Mountain Top Hardware. This list of accounts is comprehensive and you will not be adding any other accounts to the list. The rest of page 1 book 1 and leading on to page 2 provide a brief overview of the steps and process to complete the project. This document is a supplement to book 1 instructions to provide additional detailed information. The second paragraph of book 1 page 2 provides the adjusting entries that need to be completed before financial statements can be executed properly. The remainder of page two summarizes the steps of the accounting cycle to be complete for this project. Table 1 above also provides this summary of steps.

Page 3 of book 1 provides a demonstration of how numbers are recorded on accounting paper. Reviewing the debit or credit column of the journal we see there are boxes with numbers in them. The box to the right side of the dashed line is the pennies (cents) column. Note that if there are no pennies involved in the transaction the box should be left blank or a line drawn in the box. DO NOT put two little zeros in this box. The next box to the left would be the “ones” column, then continuing to the left, the “tens’ column, then the “hundreds” column. The thicker dark line between the next box would act like a comma in the number 13,560.00. The next box would be the “thousands” column and the final box would contain ten thousand and one hundred thousand digits when required. This particular journal entry will be utilized to record form 20 (different customer and numbers) when you get to that point so make a point to use this guidance if needed.

Page 4 of book 1 provides come check figures for you to compare your column totals for special journals prior to posting to the general ledger. “Income Statement” and Balance Sheet” check figures are also provided here.

Page 7 of book 1 is the first of 3 general journal pages. There are 4 transactions (of the 50) that will be recorded on this page. Those transactions (from book 3) are forms 21, 24, 39, and 45. You can make a note at the top of this page that these 4 forms are the only ones that will get recorded here.

Page 8 of book 1 is the second page of your general journal. There is a note at the top that says “Adjusting Entries Only”. Step 6 from table 1 is to journalize and post adjusting entries. The adjustments that need to be made were given on page 2 of book 1. After you have recorded and posted the transactions to the general ledger (book 2) and prepare your “Unadjusted Trial Balance”, you will journalize the adjustments on this page. Adjusting entries were introduced in chapter 3. When recording these 10 adjusting entries please record them in the order provided 1-9a/b from book 1 page 2. Skip a line between each adjusting entry.

Page 9 of book 1 is the third general journal page. There is a note at the top of the page which says “Closing Entries Only”. When you get to step 9 from table 1 you will be preparing your closing entries on this page. The following exhibit from your ebook shows the closing process for a merchandising business. Use this template to help you with your “Closing Process”.

Note that Mountain Top has three revenue accounts (the example above has only 2) and you may have more and/or different expense accounts than those listed here. Your chart of accounts in book 2 will help in this process. All accounts in the right hand column plus the S H Pilot Drawing account will get closed in this process. Also the S H Pilot Capital account will get updated and the ending balance of the account should match the ending capital number from your “Statement of Owner’s Equity” (discussed later).

Page 11 of book 1 is the first of your 4 specialized journals. The “Sales Journal” is where all sales made on account (accounts receivable) are recorded. In the front of book 3 you will find a list of our regular customers (there are 8) that purchase from us on account. You will find these same 8 customers in the accounts receivable subsidiary ledger in the back of book 2 (more about that later). Specialized journals save time journalizing and posting by creating columns for accounts involved in the sales process so that a sale can be recorded on one line instead of four lines and posting can be done at the end as a total rather than each time a sale is made. The recording process will be covered later. For now note that the column labeled “Account Debited” will be regular customer names only in this column.

Pages 12 and 13 of book 1 are the “Purchases Journal” used to record the purchase of merchandise, supplies, and other miscellaneous items from our suppliers on account (accounts payable). Our regular suppliers are listed again in the front of book 3 below our regular customers (we have 6 regular suppliers). Note that the column labeled “Account Credited” will contain the names of our regular suppliers only.

Pages 14 and 15 of book 1 are the “Cash Receipts Journal”. There are several forms that are representations of checks written to Mountain Top Hardware for payments. Each time we receive checks (and the deposit slips for cash) we enter them in the “Cash Receipts Journal”. There are three types of transactions where cash is received. 1) Regular customers paying for invoices we have issued accompanying the merchandise we have sold to them (for these checks enter the customer name in the “Account Credited” column and utilize the “accounts receivable CR” and “Cash DR” columns to record the amount of the check (note that special journals may not need to use every column for each transaction, only the ones need to record each particular transaction. Update the subsidiary ledger for accounts receivable and place a check mark in the posting reference column of the “Cash Receipts Journal’ to indicate this update has occurred. 2) payment received for something other than a regular customer payment. There are two instances in this practice set where checks are received from a party that is not one of our regular customers (one is for rental of equipment – form 3 and one is for some store supplies we returned to Mile High Office Supply – form 25.) In both of these cases utilize the “other accounts CR” column and the “Cash DR” column. Make sure in the column that say “Account Credited” to write the general ledger account that is credited (“Rent Revenue” for the first one and “Store Supplies” for the second one. The posting reference should be the account number of these accounts from the general ledger). 3) once a week at the end of the week be deposit the cash from the retail store sales (form 14 is the first of these). We utilize the “Merch Inv CR/Cost of Merch Sold DR”, “Sales CR” and “Cash DR” columns to record these transactions (see specific form instructions in the back of book 3 for more details).

Page 16 of book 1 is the “Cash Payments Journal”. You are the bookkeeper for Mountain Top Hardware and part of your job will be to pay various parties. Payments are made to 1) regular suppliers for invoices for merchandise we have purchase 2) to purchase other asset 3) to pay bills for things like electric, advertising, etc. 4) re-imbursement of expenses like sales dinners 4) to pay the owner through the drawing account. Each time a payment is made, it is recorded in the “Cash Payments Journal” (additionally you will need to write a check from book 4 – more about that later). For payments to our regular supplies – write their name in the “Account Debited Column and the amount of the check in the “Accounts Payable DR” and “Cash CR” columns. For other payments write the name of the general ledger account utilized in the “Account Debited” column Use the “Other Accounts DR”: and “Cash CR” column to complete the transaction Note: the posting reference is a √ (indicating a subsidiary ledger is updated) for payment of suppliers and the general ledger account number for other payments).

Page 17 of book 1 is for step 3 of table 1 above. Once the transactions are recorded and the totals are posted to the general ledger (see video “What do I do once all the transactions are completed”) you will be ready to complete the unadjusted trial balance. Don’t forget the date at the top. Once this is complete, it is a good time to have your work checked before proceeding to the next step. If you are an online student and cannot make it to campus, you can take a picture of this page and email it to me for validation.

Page 18 of book 1 is for step 7 from table 1 above. Once you have journalized and posted your adjusting entries you will prepare an adjusted trial balance here. Note: You cannot complete this page until you have completed step 6 of the process. Don’t forget the date. These accounts and the balance provide on this page will provide the information needed to complete the financial statements on the following pages. This is also an excellent time to get your numbers checked again before proceeding to the next step (If you are taking the class on line, you can always take a picture of this page or any page with your smart phone and forward the picture to the instructor to check your work).

Financial Statements (Step 8 from table 1)

Page 20 of book 1 is a template for your “Income statement” (don’t forget the date). The following exhibit from your textbook will provide guidance for your Multi-step income statement.

This exhibit will help in understanding which columns numbers belong in as well as guidance for some additional titles that need to be included like “gross profit”, “total selling expenses”, etc. The chart of accounts in book 2 will help you identify the accounts, the order, and the categorization of the accounts that belong on this financial statement.

Page 21 of book 1 is a template for your “Statement of Owner’s Equity”. Don’t forget the date. The following exhibit from your textbook will refresh your memory for your statement.

Pages 22 and 23 provide templates for your “Balance Sheet”. The following exhibit will help guide you to get the numbers in the proper columns and assist with additional headings for categories and totals (sub-totals). Your chart of accounts in book 2 will help get accounts in the correct order and categories.

Note the exhibit shows the “report form” for a balance sheet (all one column). Your template utilizes the “account form” where assets are listed on the left hand page and liabilities and owners equity are listed on the right hand page.

Page 24 of book 1 provides a template for the “Post Closing Trial Balance”. Step 10 from table 1 above. This is your final step to complete the project. This trial balance should only contain accounts from the general ledger that have balances following the closing process (Asset, Liabilities, and S H Pilot Capital).

Book 2

Book 2 contains your “General Ledger” and your “Subsidiary Ledgers” for Accounts Receivable and Accounts Payable. All balances for accounts have been entered as of June 1. If the balance of the account is missing, this means there is no beginning balance for that account. If you add the balances of the “Accounts Receivable Subsidiary Ledger” this number will equal the balance of “Accounts Receivable” in the general ledger. This will be true for the Accounts Payable Subsidiary Ledger and the Accounts Payable General Ledger account. Subsidiary ledgers provide the details behind the corresponding general ledger account. All transaction will eventually make their way to the general ledger through the posting process.

Book 3

Book 3 contains the business forms that represent the 50 transactions you are required to complete for step 1 of the process that will allow you to then execute steps 2-10 of the accounting cycle. This project utilized the business forms method of identifying transactions. Your textbook and CNOW have utilized the narrative form of identifying transactions. You will be required (with help) to analyze a form and determine what needs to be done to record each transaction. Note that in the back of book 3 starting on page 21 there is assistance to help you step by step in completing the first 15 forms and provide you with heads up on other unique forms. Also note there are help videos in Moodle to guide you through specific types of transaction like credit memos and recording payroll. When all else fails you can get help from the instructor or the business department lab in Meyer 102.

Book 4

Book 4 is your checkbook. The beginning balance in your book is missing. You can find out how much money you have in the checking account by checking the “Cash” account in your general ledger (book 2). There are exactly 16 checks. This project requires you write exactly 16 checks – no more no less. You are expected to keep the check stubs updated and accurate as well as filling in and signing the checks. Do not remove the checks from the book. The last page contains a check stub without the check. This is provided to facilitate the final deposit and allow you to record the ending balance in your checkbook. This balance should match the ending balance in your cash account in the general ledger provided you have recorded all transactions, postings, and checks properly and updated balances correctly from stub to stub. It would be a good idea to check in at the end of each page in the checkbook (every four check) to see if your balances are correct and that all checks recorded are in the proper order (a requirement).

Now that we are familiar with the different books and what is contained and required for each – the following will provide some additional details on completing each of the ten steps of the accounting cycle for this project. Some of the material will be a duplication of information provided to this point, however much of it will provide further clarification and details.

After reviewing this additional guidance, you should be ready to start recording transactions. If you are unable to attend the sessions where I do this for you, you should refer to page 21 of book 3 for step by step instructions on how to record transactions.

 

Additional detailed guidance

Steps 1 and 2: Analyzing / Recording Transactions and Posting to the Ledgers

The process of completing this practice set begins with recording the 50 transactions provided in book 3.

There are five possible types of entries you may have to record. Recording of the transactions is executed using one of four special journals (discussed in detail below) or via the general journal (introduced in chapter 2 of your text and utilized to record all transactions to this point). Following every journal entry the student will be required to post an update to either a subsidiary ledger or the general ledger. Posting to subsidiary ledgers will increase or decrease the amount owed by one of our regular customers to Mountain Top in the accounts receivable subsidiary ledger (book 2 pages 14-16) or increase or decrease the amount Mountain Top owes to a supplier in the Accounts Payable subsidiary ledger (book 2 pages18-19). Increases to accounts receivable originate in the sales journal while decreases to accounts receivable originate in the cash receipts journal. Increases to accounts payable originate in the purchases journal while decreases originate in the cash payments journal. These subsidiary ledgers may also require updates from activity in the general journal.

The general flow of each entry begins with book 3 which, depending on the type of transaction, will prompt a recording in a journal in book 1, which in turn will trigger a ledger (general or subsidiary) update in book 2. Some transactions will also require that a check be written in book 4. The transaction will conclude back in book 3 where you should note in the margin what was done to complete that transaction (for example if the transaction was a sale you would record in the sales journal and update the accounts receivable subsidiary ledger). Directions on the recording of specific forms can be found in the back of book three. Those instructions will supplement this discussion.

Subsidiary Ledgers:

Subsidiary ledgers are impacted by regular customer and regular supplier transactions. The accounts receivable subsidiary ledger normal balance is a debit balance. Sales (in the sales journal) to regular customers increase the customer balance. Cash receipts (checks received in the cash receipts journal) from regular customers reduce the accounts receivable balances for customers. Accounts payable subsidiary ledger normal balance is a credit. Purchases (from the purchases journal) from regular suppliers increase the balance and cash payments (recorded in the cash payments journal) reduce the balance. Updating these subsidiary ledgers results in a checkmark in the posting reference column of the specialized or general journals. The total of accounts receivable subsidiary ledger accounts should equal the accounts receivable general ledger account balance. Likewise the total of accounts payable subsidiary ledger accounts should equal the accounts payable general ledger account balance once all transactions have been posted.

Special Journals

Special journals expedite the journalizing process by providing columns to record transactions that occur regularly. Special journals also expedite the posting process by only posting the column totals to the general ledger at the end of the month rather than following each transaction. Posting references for these post are recorded below the column total. For additional guidance, see chapter 5 or the video help titled “after the transactions are completed”. The following four transaction types utilize these special journals.

 

 

Sales Journal (book 1 page 11)

Sales on account to regular customers. These customers are listed on the inside cover of book 3. The transactions are generated as a result of invoices from Mountain Top Hardware that look like this:

These invoices include the information needed to record the transaction in the sales journal. You will need the date of the invoice to record in the date column. You will need the invoice number, the name of the customer the merchandise was sold to (enter this name in the “account debited” column), the discounted amount owed to Mountain Top Hardware (noted in script “net 2% discount $XXXX at the bottom of the invoice. This amount is recorded in the “Accounts Receivable Dr./Sales Cr.” Column. You will also need the cost of merchandise sold noted on the bottom of the invoice (Cost of Merchandise Sold: $YYYY), this amount is recorded in the “cost of merchandise sold dr. / merchandise inventory cr.” column.

Purchases Journal (book 1 pages 12 and 13)

Mountain Top purchases inventory, supplies, and other items from regular suppliers. These suppliers are listed on the inside cover of book 3. The invoices received for the purchases look similar to the invoice from Mountain Top Hardware shown above but have different company logos on them. These invoices have a date received stamped on them. This is the date you will record in the purchases journal as the transaction date. Enter the supplier name in the “account credited” column. The “accounts payable cr.” column is where the total amount owed to the seller is recorded. If a discount is offered it is noted at the bottom of the invoice, otherwise the total amount from the invoice is the amount owed. Some of the purchases are completely inventory. Other purchases include inventory and supplies. One purchase includes inventory, supplies, and a display rack. Total inventory purchased from the invoice is recorded in the “merchandise inventory dr.” column. There is a column that the amount noted as supplies is recorded (supplies dr. column) and there is a section called “other accounts dr.” with a column to record the name of the account from the general ledger to charge the expense. Remember like all journal entries your total debit amount must equal your total credit amount and you must have at least one debit and one credit entry.

Cash Receipts Journal (book 1 pages 14 and 15)

Any time cash (checks are considered cash) is received it is recorded in the cash receipts journal. These receipts are usually in the form of checks. The checks contain information such as who is sending the payment and at the bottom left of the check there is an indication of what is being payed such as an invoice or other items. If the check is from one of our regular customers, enter the customer name in the “account credited” column. If the check is for something other than payment from a regular customer, then the general ledger account name being impacted is entered in this column. Payments from regular customers enter the amount of the check in “accounts receivable CR” column and in the “cash DR” column. For payment other than regular customers enter the amount in the “other accounts CR” column and “cash DR”. column. Posting is either to the subsidiary ledger to update the amount our regular customer owes or to the general ledger when checks received are for other than payment from regular customers. The other columns shown in the cash receipts journal are used for retail sales deposits made at the end of each week. Those transactions are described below.

Deposit slips – there are four sets, one for each week forms 14 and 15 are the first of these. Form 14 and those like it in each subsequent week include cash receipts of weekly sales that need recording in the cash receipts journal. The date is provided on the deposit slip which is already filled out. In the “Account credited” column enter “Cash Sales” and place a checkmark in the posting reference column. The deposit slip includes a handwritten note with the cost of merchandise sold amount to be entered in the column “Merch Inv CR/Cost of Merch. Sold DR”. The total amount of the deposit is entered in both the “Sales CR” and “Cash DR” columns. This form also requires that you record this deposit in your checkbook. Following this deposit slip is a blank deposit slip (form 15) provided to record the checks received each week (these checks are already recorded in the cash receipts journal as described in the paragraph above). This deposit slip is needed to deposit those checks in the bank and update the checkbook with this total deposit amount. There is a help video that describes how to execute these two forms. The forms help in the back of book 3 also provides guidance.

Cash Payments Journal (book 1 page 16)

Several forms in the practice set indicate payments need to be made. Most of them originate in a memo requesting an invoice or bill be paid. Toward the end of the transactions the bill itself is presented as a form and the bookkeeper (you) should know to issue a check to pay the bill and record the transaction in the cash payments journal. The bills indicated what general ledger account(s) should be charged to record the payment. All entries in the cash payments journal also require you to go to book 4 and write a check and update the check stubs with the proper information. Memos will provide the date of the transaction while bills will be stamped received with a date which becomes the transaction date. The column for check No. will include an entry from book 4 that indicated the check number used to satisfy the transaction. The “Account Debited” column will be either the name of one of our regular suppliers being paid, or the name of a general ledger account indicating an asset account or expense account being paid. If a general ledger account is being charged the amount is entered in the “other accounts DR” column. If a regular supplier is being paid the amount is entered in the “Accounts Payable Dr.” column. Regardless of the Debit, the amount of the check is entered in the “Cash CR” column. Help is available via video or forms help in the back of book 3 to assist in specifics of transactions.

Don’t forget that once all the transaction have been recorded, the columns of each special journal will be totaled and the total will be posted to the appropriate general ledger account. See chapter 5 for posting special journals or the video help in moodle.

Step 3: Unadjusted Trial Balance:

The effort you have just completed will have consumed about 75% of the time it will take to complete this project. HOWEVER you have only earned 30% of your final grade. Yes, I know, it doesn’t seem fair but hey life is not always fair. The point is don’t quit here. The remainder of what is left is the payoff for all that work. Once you have posted all your special journal column totals to the general ledger, it is time to start the unadjusted trial balance. This Unadjusted Trial Balance is in book 1 on page 17. Transfer the balances of each general ledger account to the Unadjusted Trial Balance. This is a good time to get your figures checked by your instructor or other support staff. For on line students you can take a picture of the unadjusted trial balance and send it to your instructor to validate your progress.

Step 4: Assemble and Analyze Adjustment Data

The data you will need to complete the adjusting process is found in book 1 page 2. Most of these adjustments should be familiar from chapter 3 of your textbook. The first adjustment listed in new. This adjustment is to inventory and is a result of “shrinkage” (inventory gets lost, stolen, or broken). Your general ledger balance should be more than the amount indicated by the physical count. This adjustment is meant to update the balance of the account to match to physical count number. You accomplish this by debiting cost of merchandise sold and crediting merchandise inventory for an amount that will cause the balance in the merchandise inventory to equal the physical count. Adjustments 2-6 should be very familiar. If you need additional guidance on these see chapter 3 of your textbook. Adjustment 7 is a debit to interest receivable and a credit to interest revenue. Adjustment 8 requires two debits and one credit. Adjustment 9 is new and in book 1 there is ample guidance provided with the adjusting entry. These adjusting amounts need to be journalized in book 1 page 8 and posted to the general ledger (see step 6 below).

Step 5: Prepare End of Period Spreadsheet

This step of the process is omitted move on to step 6.

Step 6: Journalize and Post Adjusting Entries (book 1 page 8)

Utilize the adjusting data provided in book 1 page 2 to assist in this process (step 4 above provides additional guidance). Please journalize the adjustments in the order provided in book 1 page 2. Once they are journalized, post these adjustments to the general ledger. Be sure to note (write adjusting entry) in the item column of the general ledger accounts.

Step 7: Prepare Adjusted Trial Balance

Once the adjustments are journalized and posted, prepare an adjusted trail balance using the updated general ledger account balances. This Adjusted Trial Balance is recorded in book 1 page 18. Use the Adjusted Trial Balance to assist in preparing the financial statements in step 8 below.

Step 8: Prepare Financial Statements

As we discovered in chapter 1 there are four financial statements. In this course we only address the first three: Income Statement, Statement of Owners Equity, and Balance Sheet (the Statement of Cash Flows is left to more advanced courses).

Templates are provided in book 1 pages 20-23 to record these financial statements.

Income Statement: The instructions to this practice set require a multi-step income statement. An example of one can be found in chapter 6 page 304 exhibit 11 in your textbook (also provided earlier in this document). Your chart of accounts (book 2 inside cover) is also valuable in helping organize and record this financial statement correctly. The example in your textbook will help you understand which columns the numbers should be recorded in and additional titles for totals and sub-totals.

Statement of Owners Equity: The statement of owner’s equity is very straight forward. Textbook page 305 Exhibit 13 provides an example if you need a refresher from chapter 1 (also provided earlier in this document).

Balance Sheet: The instructions to this practice set require a classified balance sheet. Your textbook provides an example on page 306 exhibit 14 (also provided earlier in this document). The textbook version is in the “report form” (assets on top, followed by liabilities, and then owner’s equity). The template provided is in the “account form” (assets on the left page, liabilities and owner’s equity on the right page). Additional help can be provided using the chart of accounts (book 2 inside cover).

All of the data (numbers needed) to complete these financial statements can be obtained from your Adjusted Trial Balance. Don’t’ forget to add the dates on proper form.

Step 9: Journalize and Post the Closing Entries (book 1 page 9)

The closing process is explained in chapter 4 of your textbook. Additional help about closing merchandising accounts can be found in chapter 6 on page 307 (also provided earlier in this document). Your chart of accounts can be helpful. All accounts in the right hand column will be closed in the first step of the closing process. Additionally the drawing account will be closed in the second step of the process. The closing process accomplished two things: 1) it resets the balance of temporary accounts to zero in preparation for the next accounting cycle and 2) it updates the balance of the capital account to match the ending capital calculated in the statement of owner’s equity. Remember to journalize AND post to the general ledger. When posting to the general ledger it should be noted in the “item” column that this is a “closing entry”.

Step 10 Prepare a Post Closing Trial Balance (book 1 page 24)

The final step in the accounting cycle is to prepare a post closing trial balance. Only permanent accounts (assets, liabilities, and owners capital) will have balances. Book 1 page 22 provides the template to complete this task. See chapter 4 if you need a refresher on post closing trial balance. Don’t forge the date.

Final words

This process is important to re-enforce the accounting cycle examined in chapters 1-4 and to introduced special journals (chapter 5) and merchandising business (chapter 6). There are no other assignments due during the time you are working on this practice set. It can appear overwhelming but steady progress each day will get you to the finish line on time. Procrastination will result in heart ache and stress.

Your instructor and support staff are available to help with questions and to check progress along the way. If you ask for help, you will get it. If you do not ask, we cannot read your mind and you will struggle. For distance learning students – The face to face kick off session will provide great help and assistance. If you are unable to attend, help is available via email (take pictures of pages and forward), telephone calls also work well, or your can schedule a time to meet face to face. Good luck and please ask if you do not understand something.

 

 

 

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