Rewrite
1. Label the box below to create a two-pass schedule legend.
Ans:
ES | EF | |
Float | Activity Name | |
Duration | ||
LS | LF | |
3. In the example below, label which activities are predecessors and which activities are successors.
Ans:
Predecessor: An activity which comes before another activity. So, it is activity “A” and activity “B”.
Successor: An activity that must occur after another activity. So, it is activity “C”.
5. Calculate early start, early finish, late start, late finish, and float for each of the activities in the network below. The duration of each activity is given.
Based on the analysis for the two-pass schedule:
A B C D
Duration: 12 Duration: 4 Duration: 1 Duration: 7
Early start: 0 Early start: 12 Early start: 16 Early start: 12
Early finish: 12 Early finish: 16 Early finish: 17 Early finish:19
Late start: 0 Late start: 14 Late start: 18 Late start: 12
Late finish: 12 Late finish: 18 Late finish: 19 Late finish: 19
Float: 0 Float: 2 Float: 2 Float: 0
E
Duration: 3 Early finish: 22 Late finish: 22
Early start:19 Late start: 19 Float: 0
6. Identify the critical path for the network in Exercise 5. How long should the project take?
Ans: The critical path is:
A – D – E, which has the longest path of 22 days.
9. Given the information below, create the project schedule network. Then, using the enumeration method, calculate and show all of the paths through the network. Show how long each path will take. Identify the critical path. Show the schedule on a Gantt chart showing critical and noncritical activities and float.
The critical path is
B – A – C – F – H – I, which takes 25 days.
Other paths:
B – E – H – I = 20 days
B – A – D – G – I = 23 days
Part 2 Scheduling Problem (50 points)
Complete the following:
Your child is a member of the school theater group and have been asked to prepare the schedule, etc. for a skit to be performed during the 4th of July celebration in the local village square. As a volunteer, you offer to serve as the project controller because of your expertise in schedule management.
1. Construct an AON diagram similar to the format used in the Youtube videos found in the commentary using an MS Excel spreadsheet. Ensure that you include a Start activity and a Finish activity. Include a legend (example is the one completed in Question 1, Part 1.
1. Calculate the estimated time for each activity using PERT techniques for the 3 estimates provided. Include a sample calculation.
1. Prepare a table that identifies all paths and their lengths. Which path is the critical path?
1. During the execution phase of the skit project, one of the activities on the critical path is delayed by one day. Is this serious?
1. Using the activity estimates for optimistic, pessimistic and most likely time to complete activities on the critical path, qualitatively discuss the estimate uncertainty of the critical path.
ANS: 1
2.
Different Paths are:
1. : 1-5-10-13-15
1. : 1-4-9-13-15
1. : 1-4-6-8-12-15
1. : 2-6-8-12-15
1. : 2-3-8-12-15
1. : 2-3-7-11
1. : 2-3-7-14
# | Optimistic | Most Likely | Pessimistic |
1 | 39 | 44 | 55 |
2 | 39 | 48 | 63 |
3 | 41 | 52 | 63 |
4 | 37 | 43 | 49 |
5 | 35 | 42 | 49 |
6 | 32 | 37 | 42 |
7 | 29 | 34 | 39 |
3.
Activity | Duration | Early Start | Early Finish | Late Start | Late Finish | Float |
1 | 4 | 0 | 4 | 0 | 4 | 0 |
2 | 5 | 0 | 5 | 0 | 5 | 0 |
3 | 5 | 10 | 15 | 15 | 20 | 5 |
4 | 10 | 4 | 14 | 4 | 14 | 0 |
5 | 12 | 4 | 16 | 11 | 23 | 7 |
6 | 6 | 14 | 20 | 14 | 20 | 0 |
7 | 10 | 10 | 20 | 25 | 35 | 15 |
8 | 7 | 20 | 27 | 20 | 27 | 0 |
9 | 9 | 14 | 23 | 17 | 26 | 3 |
10 | 3 | 16 | 19 | 23 | 26 | 7 |
11 | 17 | 20 | 37 | 35 | 52 | 15 |
12 | 8 | 27 | 35 | 27 | 35 | 0 |
13 | 9 | 23 | 32 | 26 | 35 | 3 |
14 | 14 | 20 | 34 | 38 | 52 | 18 |
15 | 17 | 35 | 52 | 35 | 52 | 0 |
The critical path is 1-4-6-8-12-15 = 4+10+6+7+8+17 = 52
4.
If one activity in the critical path is delayed for one day, the critical path will delay one day and the whole project will delay for a day too.
5.
If we use optimistic time for the critical path, that is 41 days, the pessimistic path is 63 days, which means 22 days of uncertainty can be saved.